x^2+4x+10=3

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Solution for x^2+4x+10=3 equation:


Simplifying
x2 + 4x + 10 = 3

Reorder the terms:
10 + 4x + x2 = 3

Solving
10 + 4x + x2 = 3

Solving for variable 'x'.

Reorder the terms:
10 + -3 + 4x + x2 = 3 + -3

Combine like terms: 10 + -3 = 7
7 + 4x + x2 = 3 + -3

Combine like terms: 3 + -3 = 0
7 + 4x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-7' to each side of the equation.
7 + 4x + -7 + x2 = 0 + -7

Reorder the terms:
7 + -7 + 4x + x2 = 0 + -7

Combine like terms: 7 + -7 = 0
0 + 4x + x2 = 0 + -7
4x + x2 = 0 + -7

Combine like terms: 0 + -7 = -7
4x + x2 = -7

The x term is 4x.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4x + 4 + x2 = -7 + 4

Reorder the terms:
4 + 4x + x2 = -7 + 4

Combine like terms: -7 + 4 = -3
4 + 4x + x2 = -3

Factor a perfect square on the left side:
(x + 2)(x + 2) = -3

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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